(n+8)+3=(n+8)+3)/2

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Solution for (n+8)+3=(n+8)+3)/2 equation: 



(n+8)+3=(n+8)+3)/2

We move all terms to the left:

(n+8)+3-((n+8)+3)/2)=0

We get rid of parentheses

n-((n+8)+3)/2)+3+8=0

We multiply all the terms by the denominator


n*2)+3+8-((n+8)+3)=0

We add all the numbers together, and all the variables

n*2)+3+8-((n+8)=0

Wy multiply elements

2n^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{4}=0$

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