(n+8)=+(n-12)

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Solution for (n+8)=+(n-12) equation: 



(n+8)=+(n-12)

We move all terms to the left:

(n+8)-(+(n-12))=0

We get rid of parentheses

n-(+(n-12))+8=0



We calculate terms in parentheses: -(+(n-12)), so:

+(n-12)

determiningTheFunctionDomain
(n-12)

We get rid of parentheses

n-12

Back to the equation:

-(n-12)



We get rid of parentheses

n-n+12+8=0

We add all the numbers together, and all the variables

20!=0

There is no solution for this equation

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