(n+9)/5=(n-1)/3

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Solution for (n+9)/5=(n-1)/3 equation: 



(n+9)/5=(n-1)/3

We move all terms to the left:

(n+9)/5-((n-1)/3)=0

We calculate fractions


n/()+(-((n-1)*5)/()=0



We calculate terms in parentheses: +(-((n-1)*5)/(), so:

-((n-1)*5)/(

We multiply all the terms by the denominator


-((n-1)*5)



We calculate terms in parentheses: -((n-1)*5), so:

(n-1)*5

We multiply parentheses

5n-5

Back to the equation:

-(5n-5)



We get rid of parentheses

-5n+5

Back to the equation:

+(-5n+5)



We get rid of parentheses

n/()-5n+5=0

We multiply all the terms by the denominator


n-5n*()+5*()=0

We add all the numbers together, and all the variables

n-5n*()=0

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