(n-1)(n+2)=0

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Solution for (n-1)(n+2)=0 equation:


Simplifying
(n + -1)(n + 2) = 0

Reorder the terms:
(-1 + n)(n + 2) = 0

Reorder the terms:
(-1 + n)(2 + n) = 0

Multiply (-1 + n) * (2 + n)
(-1(2 + n) + n(2 + n)) = 0
((2 * -1 + n * -1) + n(2 + n)) = 0
((-2 + -1n) + n(2 + n)) = 0
(-2 + -1n + (2 * n + n * n)) = 0
(-2 + -1n + (2n + n2)) = 0

Combine like terms: -1n + 2n = 1n
(-2 + 1n + n2) = 0

Solving
-2 + 1n + n2 = 0

Solving for variable 'n'.

Factor a trinomial.
(-2 + -1n)(1 + -1n) = 0

Subproblem 1

Set the factor '(-2 + -1n)' equal to zero and attempt to solve: Simplifying -2 + -1n = 0 Solving -2 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '2' to each side of the equation. -2 + 2 + -1n = 0 + 2 Combine like terms: -2 + 2 = 0 0 + -1n = 0 + 2 -1n = 0 + 2 Combine like terms: 0 + 2 = 2 -1n = 2 Divide each side by '-1'. n = -2 Simplifying n = -2

Subproblem 2

Set the factor '(1 + -1n)' equal to zero and attempt to solve: Simplifying 1 + -1n = 0 Solving 1 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1n = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1n = 0 + -1 -1n = 0 + -1 Combine like terms: 0 + -1 = -1 -1n = -1 Divide each side by '-1'. n = 1 Simplifying n = 1

Solution

n = {-2, 1}

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