(n-1)=-2(3+n)

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Solution for (n-1)=-2(3+n) equation: 



(n-1)=-2(3+n)

We move all terms to the left:

(n-1)-(-2(3+n))=0

We add all the numbers together, and all the variables

(n-1)-(-2(n+3))=0

We get rid of parentheses

n-(-2(n+3))-1=0



We calculate terms in parentheses: -(-2(n+3)), so:

-2(n+3)

We multiply parentheses

-2n-6

Back to the equation:

-(-2n-6)



We get rid of parentheses

n+2n+6-1=0

We add all the numbers together, and all the variables

3n+5=0

We move all terms containing n to the left, all other terms to the right

3n=-5

n=-5/3

n=-1+2/3

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