(n-12)+48=38+29

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Solution for (n-12)+48=38+29 equation: 



(n-12)+48=38+29

We move all terms to the left:

(n-12)+48-(38+29)=0

We add all the numbers together, and all the variables

(n-12)+48-67=0

We add all the numbers together, and all the variables

(n-12)-19=0

We get rid of parentheses

n-12-19=0

We add all the numbers together, and all the variables

n-31=0

We move all terms containing n to the left, all other terms to the right

n=31

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