(n-2)(5n-6)=0

Solution for (n-2)(5n-6)=0 equation:

(n-2)(5n-6)=0

We multiply parentheses ..

(+5n^2-6n-10n+12)=0

We get rid of parentheses

5n^2-6n-10n+12=0

We add all the numbers together, and all the variables

5n^2-16n+12=0

a = 5; b = -16; c = +12;
Δ = b2-4ac
Δ = -162-4·5·12
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-4}{2*5}=\frac{12}{10}
=1+1/5
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+4}{2*5}=\frac{20}{10}
=2
$