(n-2)(n-3)(n-4)(n-5)=0

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Solution for (n-2)(n-3)(n-4)(n-5)=0 equation: 



(n-2)(n-3)(n-4)(n-5)=0

We multiply parentheses ..

(+n^2-3n-2n+6)(n-4)(n-5)=0

We multiply parentheses ..

(+n^2-3n-2n+6)(+n^2-5n-4n+20)=0

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