(n-2)(n=2)=27

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Solution for (n-2)(n=2)=27 equation: 



(n-2)(n=2)=27

We move all terms to the left:

(n-2)(n-(2))=0

We multiply parentheses ..

(+n^2-2n-2n+4)=0

We get rid of parentheses

n^2-2n-2n+4=0

We add all the numbers together, and all the variables

n^2-4n+4=0

a = 1; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·1·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{4}{2}=2$

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