(n-3)(n-1)(n+1)=0

Solution for (n-3)(n-1)(n+1)=0 equation:

Simplifying
(n + -3)(n + -1)(n + 1) = 0

Reorder the terms:
(-3 + n)(n + -1)(n + 1) = 0

Reorder the terms:
(-3 + n)(-1 + n)(n + 1) = 0

Reorder the terms:
(-3 + n)(-1 + n)(1 + n) = 0

Multiply (-3 + n) * (-1 + n)
(-3(-1 + n) + n(-1 + n))(1 + n) = 0
((-1 * -3 + n * -3) + n(-1 + n))(1 + n) = 0
((3 + -3n) + n(-1 + n))(1 + n) = 0
(3 + -3n + (-1 * n + n * n))(1 + n) = 0
(3 + -3n + (-1n + n2))(1 + n) = 0

Combine like terms: -3n + -1n = -4n
(3 + -4n + n2)(1 + n) = 0

Multiply (3 + -4n + n2) * (1 + n)
(3(1 + n) + -4n * (1 + n) + n2(1 + n)) = 0
((1 * 3 + n * 3) + -4n * (1 + n) + n2(1 + n)) = 0
((3 + 3n) + -4n * (1 + n) + n2(1 + n)) = 0
(3 + 3n + (1 * -4n + n * -4n) + n2(1 + n)) = 0
(3 + 3n + (-4n + -4n2) + n2(1 + n)) = 0
(3 + 3n + -4n + -4n2 + (1 * n2 + n * n2)) = 0
(3 + 3n + -4n + -4n2 + (1n2 + n3)) = 0

Combine like terms: 3n + -4n = -1n
(3 + -1n + -4n2 + 1n2 + n3) = 0

Combine like terms: -4n2 + 1n2 = -3n2
(3 + -1n + -3n2 + n3) = 0

Solving
3 + -1n + -3n2 + n3 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.