(n-4)(n+4)=n2-16

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Solution for (n-4)(n+4)=n2-16 equation: 



(n-4)(n+4)=n2-16

We move all terms to the left:

(n-4)(n+4)-(n2-16)=0

We add all the numbers together, and all the variables

-(+n^2-16)+(n-4)(n+4)=0

We use the square of the difference formula

-(+n^2-16)+n^2-16=0

We get rid of parentheses

-n^2+n^2+16-16=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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