(n-4)-3(n+2)=n-47

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Solution for (n-4)-3(n+2)=n-47 equation: 



(n-4)-3(n+2)=n-47

We move all terms to the left:

(n-4)-3(n+2)-(n-47)=0

We multiply parentheses

(n-4)-3n-(n-47)-6=0

We get rid of parentheses

n-3n-n-4+47-6=0

We add all the numbers together, and all the variables

-3n+37=0

We move all terms containing n to the left, all other terms to the right

-3n=-37

n=-37/-3

n=12+1/3

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