(n-4)/8=(n+4)/2

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Solution for (n-4)/8=(n+4)/2 equation: 



(n-4)/8=(n+4)/2

We move all terms to the left:

(n-4)/8-((n+4)/2)=0

We calculate fractions


n/()+(-((n+4)*8)/()=0



We calculate terms in parentheses: +(-((n+4)*8)/(), so:

-((n+4)*8)/(

We multiply all the terms by the denominator


-((n+4)*8)



We calculate terms in parentheses: -((n+4)*8), so:

(n+4)*8

We multiply parentheses

8n+32

Back to the equation:

-(8n+32)



We get rid of parentheses

-8n-32

Back to the equation:

+(-8n-32)



We get rid of parentheses

n/()-8n-32=0

We multiply all the terms by the denominator


n-8n*()-32*()=0

We add all the numbers together, and all the variables

n-8n*()=0

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