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(n-5/2n)-(3/4n)=1/4
We move all terms to the left:
(n-5/2n)-(3/4n)-(1/4)=0
Domain of the equation: 2n)!=0
n!=0/1
n!=0
n∈R
Domain of the equation: 4n)!=0We add all the numbers together, and all the variables
n!=0/1
n!=0
n∈R
(+n-5/2n)-(+3/4n)-(+1/4)=0
We get rid of parentheses
n-5/2n-3/4n-1/4=0
We calculate fractions
n+(-320n)/128n^2+(-6n)/128n^2+(-2n)/128n^2=0
We multiply all the terms by the denominator
n*128n^2+(-320n)+(-6n)+(-2n)=0
Wy multiply elements
128n^3+(-320n)+(-6n)+(-2n)=0
We get rid of parentheses
128n^3-320n-6n-2n=0
We do not support enpression: n^3
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