(n-6)(n-5)(n-4)=1/210

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Solution for (n-6)(n-5)(n-4)=1/210 equation: 



(n-6)(n-5)(n-4)=1/210

We move all terms to the left:

(n-6)(n-5)(n-4)-(1/210)=0

We add all the numbers together, and all the variables

(n-6)(n-5)(n-4)-(+1/210)=0

We get rid of parentheses

(n-6)(n-5)(n-4)-1/210=0

We multiply parentheses ..

(+n^2-5n-6n+30)(n-4)-1/210=0

We multiply all the terms by the denominator


((+n^2-5n-6n+30)(n-4))*210-1=0

We move all terms containing n to the left, all other terms to the right

((+n^2-5n-6n+30)(n-4))*210=1

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