(n-6)/3=(n-2/9)

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Solution for (n-6)/3=(n-2/9) equation: 



(n-6)/3=(n-2/9)

We move all terms to the left:

(n-6)/3-((n-2/9))=0

We add all the numbers together, and all the variables

(n-6)/3-((+n-2/9))=0

We calculate fractions


n/()+(-((+n-2*3)/()=0



We calculate terms in parentheses: +(-((+n-2*3)/(), so:

-((+n-2*3)/(

We add all the numbers together, and all the variables

-((n-6)/(

We multiply all the terms by the denominator


-((n-6)



We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

(n-6





We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

(n-6





We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

(n-6





We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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We calculate terms in parentheses: -((n-6), so:

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