(n/3)-(1/6)=(1/2)

Solution for (n/3)-(1/6)=(1/2) equation:

(n/3)-(1/6)=(1/2)

We move all terms to the left:

(n/3)-(1/6)-((1/2))=0

We add all the numbers together, and all the variables

(+n/3)-(+1/6)-((+1/2))=0

We get rid of parentheses

n/3-1/6-((+1/2))=0

We calculate fractions


24n^2/()+()/()+()/()=0

We add all the numbers together, and all the variables

24n^2/()+2=0

We multiply all the terms by the denominator


24n^2+2*()=0

We add all the numbers together, and all the variables

24n^2=0

a = 24; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·24·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{0}{48}=0$