(n/5)=(2n+4)/6

Solution for (n/5)=(2n+4)/6 equation:

(n/5)=(2n+4)/6

We move all terms to the left:

(n/5)-((2n+4)/6)=0

We add all the numbers together, and all the variables

(+n/5)-((2n+4)/6)=0

We get rid of parentheses

n/5-((2n+4)/6)=0

We calculate fractions


6n^2/()+(-((2n+4)*5)/()=0


We calculate terms in parentheses: +(-((2n+4)*5)/(), so:

-((2n+4)*5)/(

We multiply all the terms by the denominator


-((2n+4)*5)


We calculate terms in parentheses: -((2n+4)*5), so:

(2n+4)*5

We multiply parentheses

10n+20

Back to the equation:

-(10n+20)


We get rid of parentheses

-10n-20

Back to the equation:

+(-10n-20)


We get rid of parentheses

6n^2/()-10n-20=0

We multiply all the terms by the denominator


6n^2-10n*()-20*()=0

We add all the numbers together, and all the variables

6n^2-10n*()=0