(n=7)(3n+5)

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Solution for (n=7)(3n+5) equation: 



(n=7)(3n+5)

We move all terms to the left:

(n-(7)(3n+5))=0



We calculate terms in parentheses: +(n-7(3n+5)), so:

n-7(3n+5)

We multiply parentheses

n-21n-35

We add all the numbers together, and all the variables

-20n-35

Back to the equation:

+(-20n-35)



We get rid of parentheses

-20n-35=0

We move all terms containing n to the left, all other terms to the right

-20n=35

n=35/-20

n=-1+3/4

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