(n=7)(3n+5)

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Solution for (n=7)(3n+5) equation:



(n=7)(3n+5)
We move all terms to the left:
(n-(7)(3n+5))=0
We calculate terms in parentheses: +(n-7(3n+5)), so:
n-7(3n+5)
We multiply parentheses
n-21n-35
We add all the numbers together, and all the variables
-20n-35
Back to the equation:
+(-20n-35)
We get rid of parentheses
-20n-35=0
We move all terms containing n to the left, all other terms to the right
-20n=35
n=35/-20
n=-1+3/4

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