(p+1)(p+1)=25

Solution for (p+1)(p+1)=25 equation:

(p+1)(p+1)=25

We move all terms to the left:

(p+1)(p+1)-(25)=0

We multiply parentheses ..

(+p^2+p+p+1)-25=0

We get rid of parentheses

p^2+p+p+1-25=0

We add all the numbers together, and all the variables

p^2+2p-24=0

a = 1; b = 2; c = -24;
Δ = b2-4ac
Δ = 22-4·1·(-24)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*1}=\frac{-12}{2}
=-6
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*1}=\frac{8}{2}
=4
$