(p+1)(p+7)=0

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Solution for (p+1)(p+7)=0 equation:



(p+1)(p+7)=0
We multiply parentheses ..
(+p^2+7p+p+7)=0
We get rid of parentheses
p^2+7p+p+7=0
We add all the numbers together, and all the variables
p^2+8p+7=0
a = 1; b = 8; c = +7;
Δ = b2-4ac
Δ = 82-4·1·7
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-6}{2*1}=\frac{-14}{2} =-7 $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+6}{2*1}=\frac{-2}{2} =-1 $

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