(p+2)/8+p/8=(p-8)/6+1

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Solution for (p+2)/8+p/8=(p-8)/6+1 equation: 



(p+2)/8+p/8=(p-8)/6+1

We move all terms to the left:

(p+2)/8+p/8-((p-8)/6+1)=0

We calculate fractions


(7p+2)/()+(-((p-8)*8)/()=0



We calculate terms in parentheses: +(-((p-8)*8)/(), so:

-((p-8)*8)/(

We multiply all the terms by the denominator


-((p-8)*8)



We calculate terms in parentheses: -((p-8)*8), so:

(p-8)*8

We multiply parentheses

8p-64

Back to the equation:

-(8p-64)



We get rid of parentheses

-8p+64

Back to the equation:

+(-8p+64)



We get rid of parentheses

(7p+2)/()-8p+64=0

We multiply all the terms by the denominator


(7p+2)-8p*()+64*()=0

We add all the numbers together, and all the variables

(7p+2)-8p*()=0

We get rid of parentheses

7p-8p*()+2=0

We move all terms containing p to the left, all other terms to the right

7p-8p*()=-2

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