(p+2)/8+p/8=(p-8)/6+1

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Solution for (p+2)/8+p/8=(p-8)/6+1 equation:



(p+2)/8+p/8=(p-8)/6+1
We move all terms to the left:
(p+2)/8+p/8-((p-8)/6+1)=0
We calculate fractions
(7p+2)/()+(-((p-8)*8)/()=0
We calculate terms in parentheses: +(-((p-8)*8)/(), so:
-((p-8)*8)/(
We multiply all the terms by the denominator
-((p-8)*8)
We calculate terms in parentheses: -((p-8)*8), so:
(p-8)*8
We multiply parentheses
8p-64
Back to the equation:
-(8p-64)
We get rid of parentheses
-8p+64
Back to the equation:
+(-8p+64)
We get rid of parentheses
(7p+2)/()-8p+64=0
We multiply all the terms by the denominator
(7p+2)-8p*()+64*()=0
We add all the numbers together, and all the variables
(7p+2)-8p*()=0
We get rid of parentheses
7p-8p*()+2=0
We move all terms containing p to the left, all other terms to the right
7p-8p*()=-2

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