(p+3)(8p+1)=0

Solution for (p+3)(8p+1)=0 equation:

(p+3)(8p+1)=0

We multiply parentheses ..

(+8p^2+p+24p+3)=0

We get rid of parentheses

8p^2+p+24p+3=0

We add all the numbers together, and all the variables

8p^2+25p+3=0

a = 8; b = 25; c = +3;
Δ = b2-4ac
Δ = 252-4·8·3
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(25)-23}{2*8}=\frac{-48}{16}
=-3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(25)+23}{2*8}=\frac{-2}{16}
=-1/8
$