(p+3)(p-2)=(p-3)(p+6)-2(p-6)

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Solution for (p+3)(p-2)=(p-3)(p+6)-2(p-6) equation: 



(p+3)(p-2)=(p-3)(p+6)-2(p-6)

We move all terms to the left:

(p+3)(p-2)-((p-3)(p+6)-2(p-6))=0

We multiply parentheses ..

(+p^2-2p+3p-6)-((p-3)(p+6)-2(p-6))=0



We calculate terms in parentheses: -((p-3)(p+6)-2(p-6)), so:

(p-3)(p+6)-2(p-6)

We multiply parentheses

(p-3)(p+6)-2p+12

We multiply parentheses ..

(+p^2+6p-3p-18)-2p+12

We get rid of parentheses

p^2+6p-3p-2p-18+12

We add all the numbers together, and all the variables

p^2+p-6

Back to the equation:

-(p^2+p-6)



We get rid of parentheses

p^2-p^2-2p+3p-p-6+6=0

We add all the numbers together, and all the variables

=0

p=0/1

p=0

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