If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x in (-oo:+oo)
(4*p-9)/r+p+3 = 0
(4*p-9)/r+(p*r)/r+(3*r)/r = 0
4*p+p*r+3*r-9 = 0
(4*p+p*r+3*r-9)/r = 0
(4*p+p*r+3*r-9)/r = 0 // * r
4*p+p*r+3*r-9 = 0
x belongs to the empty set
| 6(4x-8)= | | z+9.8=3.1 | | (p+3)/r+(4p-9)/r | | .3x^2-11.1x+85.8=0 | | 3x^2-11.1x+85.8=0 | | 24=7y+4 | | -(4x+2)-6(x+3)=4-(7x+1) | | -(7y+5)-(6y-6)=-4 | | 5x=(3x-2)(m+7) | | x+2/1=-9/1 | | 5x+14=6x+2 | | 5x-4x=1 | | x^4-3x^2+2x=0 | | (7/5)/(7/20) | | r/-1=-3 | | 6x+2+3x+15=180 | | 4=-2(4.5p+2.5) | | p=2(16)+2(80) | | 5x^2/x=4x+1 | | 5x^2+x^2=0 | | 7.36=2*3.14*r | | 4x+16=180 | | x=-14/4-3/4 | | 2x(5)+x(10)=600 | | 3x^2-104.40x+896.28=0 | | A=(1/2h)(b1+b2) | | 3x-1/2(2x+20)=-2 | | 39/49x35/99x27/65 | | 4/11x=28 | | (1/3x)-(2/3)+(1/5x)=1 | | n+37=20 | | 9(Z+4)-2(Z-1)=2(Z-4)+4(Z-3) |