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(p+6)*p=56
We move all terms to the left:
(p+6)*p-(56)=0
We multiply parentheses
p^2+6p-56=0
a = 1; b = 6; c = -56;
Δ = b2-4ac
Δ = 62-4·1·(-56)
Δ = 260
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260}=\sqrt{4*65}=\sqrt{4}*\sqrt{65}=2\sqrt{65}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{65}}{2*1}=\frac{-6-2\sqrt{65}}{2} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{65}}{2*1}=\frac{-6+2\sqrt{65}}{2} $
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