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(p+7)(p+7)=0
We multiply parentheses ..
(+p^2+7p+7p+49)=0
We get rid of parentheses
p^2+7p+7p+49=0
We add all the numbers together, and all the variables
p^2+14p+49=0
a = 1; b = 14; c = +49;
Δ = b2-4ac
Δ = 142-4·1·49
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$p=\frac{-b}{2a}=\frac{-14}{2}=-7$
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