(p+8)(7p+1)=0

Solution for (p+8)(7p+1)=0 equation:

(p+8)(7p+1)=0

We multiply parentheses ..

(+7p^2+p+56p+8)=0

We get rid of parentheses

7p^2+p+56p+8=0

We add all the numbers together, and all the variables

7p^2+57p+8=0

a = 7; b = 57; c = +8;
Δ = b2-4ac
Δ = 572-4·7·8
Δ = 3025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3025}=55$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(57)-55}{2*7}=\frac{-112}{14}
=-8
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(57)+55}{2*7}=\frac{-2}{14}
=-1/7
$