(p-3)(p+5)(p-3)=(p+8)

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Solution for (p-3)(p+5)(p-3)=(p+8) equation: 



(p-3)(p+5)(p-3)=(p+8)

We move all terms to the left:

(p-3)(p+5)(p-3)-((p+8))=0

We multiply parentheses ..

(+p^2+5p-3p-15)(p-3)-((p+8))=0



We calculate terms in parentheses: -((p+8)), so:

(p+8)

We get rid of parentheses

p+8

Back to the equation:

-(p+8)



We get rid of parentheses

(+p^2+5p-3p-15)(p-3)-p-8=0

We add all the numbers together, and all the variables

(+p^2+5p-3p-15)(p-3)-1p-8=0

We move all terms containing p to the left, all other terms to the right

(+p^2+5p-3p-15)(p-3)-1p=8

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