(p-3)(p+5)=(p-3)(p+8)

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Solution for (p-3)(p+5)=(p-3)(p+8) equation: 



(p-3)(p+5)=(p-3)(p+8)

We move all terms to the left:

(p-3)(p+5)-((p-3)(p+8))=0

We multiply parentheses ..

(+p^2+5p-3p-15)-((p-3)(p+8))=0



We calculate terms in parentheses: -((p-3)(p+8)), so:

(p-3)(p+8)

We multiply parentheses ..

(+p^2+8p-3p-24)

We get rid of parentheses

p^2+8p-3p-24

We add all the numbers together, and all the variables

p^2+5p-24

Back to the equation:

-(p^2+5p-24)



We get rid of parentheses

p^2-p^2+5p-3p-5p-15+24=0

We add all the numbers together, and all the variables

-3p+9=0

We move all terms containing p to the left, all other terms to the right

-3p=-9

p=-9/-3

p=+3

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