(p-4)/6=(p+2)/12

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Solution for (p-4)/6=(p+2)/12 equation: 



(p-4)/6=(p+2)/12

We move all terms to the left:

(p-4)/6-((p+2)/12)=0

We calculate fractions


p/()+(-((p+2)*6)/()=0



We calculate terms in parentheses: +(-((p+2)*6)/(), so:

-((p+2)*6)/(

We multiply all the terms by the denominator


-((p+2)*6)



We calculate terms in parentheses: -((p+2)*6), so:

(p+2)*6

We multiply parentheses

6p+12

Back to the equation:

-(6p+12)



We get rid of parentheses

-6p-12

Back to the equation:

+(-6p-12)



We get rid of parentheses

p/()-6p-12=0

We multiply all the terms by the denominator


p-6p*()-12*()=0

We add all the numbers together, and all the variables

p-6p*()=0

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