(p-5)(p+3)=-7

Solution for (p-5)(p+3)=-7 equation:

(p-5)(p+3)=-7

We move all terms to the left:

(p-5)(p+3)-(-7)=0

We add all the numbers together, and all the variables

(p-5)(p+3)+7=0

We multiply parentheses ..

(+p^2+3p-5p-15)+7=0

We get rid of parentheses

p^2+3p-5p-15+7=0

We add all the numbers together, and all the variables

p^2-2p-8=0

a = 1; b = -2; c = -8;
Δ = b2-4ac
Δ = -22-4·1·(-8)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-6}{2*1}=\frac{-4}{2}
=-2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+6}{2*1}=\frac{8}{2}
=4
$