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(p-6)(8p-5)=0
We multiply parentheses ..
(+8p^2-5p-48p+30)=0
We get rid of parentheses
8p^2-5p-48p+30=0
We add all the numbers together, and all the variables
8p^2-53p+30=0
a = 8; b = -53; c = +30;
Δ = b2-4ac
Δ = -532-4·8·30
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1849}=43$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-53)-43}{2*8}=\frac{10}{16} =5/8 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-53)+43}{2*8}=\frac{96}{16} =6 $
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