(p-6)(p+7)=(p+3)(p-11)

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Solution for (p-6)(p+7)=(p+3)(p-11) equation:



(p-6)(p+7)=(p+3)(p-11)
We move all terms to the left:
(p-6)(p+7)-((p+3)(p-11))=0
We multiply parentheses ..
(+p^2+7p-6p-42)-((p+3)(p-11))=0
We calculate terms in parentheses: -((p+3)(p-11)), so:
(p+3)(p-11)
We multiply parentheses ..
(+p^2-11p+3p-33)
We get rid of parentheses
p^2-11p+3p-33
We add all the numbers together, and all the variables
p^2-8p-33
Back to the equation:
-(p^2-8p-33)
We get rid of parentheses
p^2-p^2+7p-6p+8p-42+33=0
We add all the numbers together, and all the variables
9p-9=0
We move all terms containing p to the left, all other terms to the right
9p=9
p=9/9
p=1

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