(p-6)(p+7)=(p+3)(p-11)

Solution for (p-6)(p+7)=(p+3)(p-11) equation:

(p-6)(p+7)=(p+3)(p-11)

We move all terms to the left:

(p-6)(p+7)-((p+3)(p-11))=0

We multiply parentheses ..

(+p^2+7p-6p-42)-((p+3)(p-11))=0


We calculate terms in parentheses: -((p+3)(p-11)), so:

(p+3)(p-11)

We multiply parentheses ..

(+p^2-11p+3p-33)

We get rid of parentheses

p^2-11p+3p-33

We add all the numbers together, and all the variables

p^2-8p-33

Back to the equation:

-(p^2-8p-33)


We get rid of parentheses

p^2-p^2+7p-6p+8p-42+33=0

We add all the numbers together, and all the variables

9p-9=0

We move all terms containing p to the left, all other terms to the right

9p=9

p=9/9

p=1