(q+1)(q+2)=0

Solution for (q+1)(q+2)=0 equation:

Simplifying
(q + 1)(q + 2) = 0

Reorder the terms:
(1 + q)(q + 2) = 0

Reorder the terms:
(1 + q)(2 + q) = 0

Multiply (1 + q) * (2 + q)
(1(2 + q) + q(2 + q)) = 0
((2 * 1 + q * 1) + q(2 + q)) = 0
((2 + 1q) + q(2 + q)) = 0
(2 + 1q + (2 * q + q * q)) = 0
(2 + 1q + (2q + q2)) = 0

Combine like terms: 1q + 2q = 3q
(2 + 3q + q2) = 0

Solving
2 + 3q + q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(2 + q)(1 + q) = 0

Subproblem 1
Set the factor '(2 + q)' equal to zero and attempt to solve:

Simplifying
2 + q = 0

Solving
2 + q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + q = 0 + -2

Combine like terms: 2 + -2 = 0
0 + q = 0 + -2
q = 0 + -2

Combine like terms: 0 + -2 = -2
q = -2

Simplifying
q = -2
Subproblem 2
Set the factor '(1 + q)' equal to zero and attempt to solve:

Simplifying
1 + q = 0

Solving
1 + q = 0

Move all terms containing q to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + q = 0 + -1

Combine like terms: 1 + -1 = 0
0 + q = 0 + -1
q = 0 + -1

Combine like terms: 0 + -1 = -1
q = -1

Simplifying
q = -1
Solution
q = {-2, -1}