(q+1)/2=(q-1)/3

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Solution for (q+1)/2=(q-1)/3 equation: 



(q+1)/2=(q-1)/3

We move all terms to the left:

(q+1)/2-((q-1)/3)=0

We calculate fractions


q/()+(-((q-1)*2)/()=0



We calculate terms in parentheses: +(-((q-1)*2)/(), so:

-((q-1)*2)/(

We multiply all the terms by the denominator


-((q-1)*2)



We calculate terms in parentheses: -((q-1)*2), so:

(q-1)*2

We multiply parentheses

2q-2

Back to the equation:

-(2q-2)



We get rid of parentheses

-2q+2

Back to the equation:

+(-2q+2)



We get rid of parentheses

q/()-2q+2=0

We multiply all the terms by the denominator


q-2q*()+2*()=0

We add all the numbers together, and all the variables

q-2q*()=0

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