(q+2)/(5)=(2q-11)/(7)

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Solution for (q+2)/(5)=(2q-11)/(7) equation: 



(q+2)/(5)=(2q-11)/(7)

We move all terms to the left:

(q+2)/(5)-((2q-11)/(7))=0

We calculate fractions


q/()+(-((2q-11)*5)/()=0



We calculate terms in parentheses: +(-((2q-11)*5)/(), so:

-((2q-11)*5)/(

We multiply all the terms by the denominator


-((2q-11)*5)



We calculate terms in parentheses: -((2q-11)*5), so:

(2q-11)*5

We multiply parentheses

10q-55

Back to the equation:

-(10q-55)



We get rid of parentheses

-10q+55

Back to the equation:

+(-10q+55)



We get rid of parentheses

q/()-10q+55=0

We multiply all the terms by the denominator


q-10q*()+55*()=0

We add all the numbers together, and all the variables

q-10q*()=0

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