(q+2)/5=(2q+11)/7

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Solution for (q+2)/5=(2q+11)/7 equation: 



(q+2)/5=(2q+11)/7

We move all terms to the left:

(q+2)/5-((2q+11)/7)=0

We calculate fractions


q/()+(-((2q+11)*5)/()=0



We calculate terms in parentheses: +(-((2q+11)*5)/(), so:

-((2q+11)*5)/(

We multiply all the terms by the denominator


-((2q+11)*5)



We calculate terms in parentheses: -((2q+11)*5), so:

(2q+11)*5

We multiply parentheses

10q+55

Back to the equation:

-(10q+55)



We get rid of parentheses

-10q-55

Back to the equation:

+(-10q-55)



We get rid of parentheses

q/()-10q-55=0

We multiply all the terms by the denominator


q-10q*()-55*()=0

We add all the numbers together, and all the variables

q-10q*()=0

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