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(q+4)(q-3)=(q+2)(q-1)
We move all terms to the left:
(q+4)(q-3)-((q+2)(q-1))=0
We multiply parentheses ..
(+q^2-3q+4q-12)-((q+2)(q-1))=0
We calculate terms in parentheses: -((q+2)(q-1)), so:We get rid of parentheses
(q+2)(q-1)
We multiply parentheses ..
(+q^2-1q+2q-2)
We get rid of parentheses
q^2-1q+2q-2
We add all the numbers together, and all the variables
q^2+q-2
Back to the equation:
-(q^2+q-2)
q^2-q^2-3q+4q-q-12+2=0
We add all the numbers together, and all the variables
-10!=0
There is no solution for this equation
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