(q+5)/3+(q-2)/2=7/8

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Solution for (q+5)/3+(q-2)/2=7/8 equation: 


q in (-oo:+oo)

(q+5)/3+(q-2)/2 = 7/8 // - 7/8

(q+5)/3+(q-2)/2-(7/8) = 0

(q+5)/3+(q-2)/2-7/8 = 0

(2*8*(q+5))/(2*3*8)+(3*8*(q-2))/(2*3*8)+(-7*2*3)/(2*3*8) = 0

2*8*(q+5)+3*8*(q-2)-7*2*3 = 0

40*q-42+32 = 0

40*q-10 = 0

(40*q-10)/(2*3*8) = 0

(40*q-10)/(2*3*8) = 0 // * 2*3*8

40*q-10 = 0

40*q-10 = 0 // + 10

40*q = 10 // : 40

q = 10/40

q = 1/4

q = 1/4

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