(q-2)/(3)=(q-1)/(q+3)

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Solution for (q-2)/(3)=(q-1)/(q+3) equation:


D( q )

q+3 = 0

q+3 = 0

q+3 = 0

q+3 = 0 // - 3

q = -3

q in (-oo:-3) U (-3:+oo)

(q-2)/3 = (q-1)/(q+3) // - (q-1)/(q+3)

(q-2)/3-((q-1)/(q+3)) = 0

(q-2)/3+(-1*(q-1))/(q+3) = 0

((q-2)*(q+3))/(3*(q+3))+(-1*3*(q-1))/(3*(q+3)) = 0

(q-2)*(q+3)-1*3*(q-1) = 0

q^2-2*q-3 = 0

q^2-2*q-3 = 0

q^2-2*q-3 = 0

DELTA = (-2)^2-(-3*1*4)

DELTA = 16

DELTA > 0

q = (16^(1/2)+2)/(1*2) or q = (2-16^(1/2))/(1*2)

q = 3 or q = -1

(q+1)*(q-3) = 0

((q+1)*(q-3))/(3*(q+3)) = 0

((q+1)*(q-3))/(3*(q+3)) = 0 // * 3*(q+3)

(q+1)*(q-3) = 0

( q+1 )

q+1 = 0 // - 1

q = -1

( q-3 )

q-3 = 0 // + 3

q = 3

q in { -1, 3 }

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