(q-7)(q-5)=

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Solution for (q-7)(q-5)= equation:


Simplifying
(q + -7)(q + -5) = 0

Reorder the terms:
(-7 + q)(q + -5) = 0

Reorder the terms:
(-7 + q)(-5 + q) = 0

Multiply (-7 + q) * (-5 + q)
(-7(-5 + q) + q(-5 + q)) = 0
((-5 * -7 + q * -7) + q(-5 + q)) = 0
((35 + -7q) + q(-5 + q)) = 0
(35 + -7q + (-5 * q + q * q)) = 0
(35 + -7q + (-5q + q2)) = 0

Combine like terms: -7q + -5q = -12q
(35 + -12q + q2) = 0

Solving
35 + -12q + q2 = 0

Solving for variable 'q'.

Factor a trinomial.
(5 + -1q)(7 + -1q) = 0

Subproblem 1

Set the factor '(5 + -1q)' equal to zero and attempt to solve: Simplifying 5 + -1q = 0 Solving 5 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-5' to each side of the equation. 5 + -5 + -1q = 0 + -5 Combine like terms: 5 + -5 = 0 0 + -1q = 0 + -5 -1q = 0 + -5 Combine like terms: 0 + -5 = -5 -1q = -5 Divide each side by '-1'. q = 5 Simplifying q = 5

Subproblem 2

Set the factor '(7 + -1q)' equal to zero and attempt to solve: Simplifying 7 + -1q = 0 Solving 7 + -1q = 0 Move all terms containing q to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + -1q = 0 + -7 Combine like terms: 7 + -7 = 0 0 + -1q = 0 + -7 -1q = 0 + -7 Combine like terms: 0 + -7 = -7 -1q = -7 Divide each side by '-1'. q = 7 Simplifying q = 7

Solution

q = {5, 7}

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