(q/2)+25=(100/q)+20

Solution for (q/2)+25=(100/q)+20 equation:

(q/2)+25=(100/q)+20

We move all terms to the left:

(q/2)+25-((100/q)+20)=0


Domain of the equation: q)+20)!=0

q!=0/1

q!=0

q∈R


We add all the numbers together, and all the variables

(+q/2)-((+100/q)+20)+25=0

We get rid of parentheses

q/2-((+100/q)+20)+25=0

We calculate fractions


q^2/2q+()/2q+25=0

We multiply all the terms by the denominator


q^2+25*2q+()=0

We add all the numbers together, and all the variables

q^2+25*2q=0

Wy multiply elements

q^2+50q=0

a = 1; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·1·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*1}=\frac{-100}{2}
=-50
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*1}=\frac{0}{2}
=0
$