(r+5)+(3r-14)=35

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Solution for (r+5)+(3r-14)=35 equation: 



(r+5)+(3r-14)=35

We move all terms to the left:

(r+5)+(3r-14)-(35)=0

We get rid of parentheses

r+3r+5-14-35=0

We add all the numbers together, and all the variables

4r-44=0

We move all terms containing r to the left, all other terms to the right

4r=44

r=44/4

r=11

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