(r+50)=r2+80

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Solution for (r+50)=r2+80 equation: 



(r+50)=r2+80

We move all terms to the left:

(r+50)-(r2+80)=0

We add all the numbers together, and all the variables

-(+r^2+80)+(r+50)=0

We get rid of parentheses

-r^2+r-80+50=0

We add all the numbers together, and all the variables

-1r^2+r-30=0

a = -1; b = 1; c = -30;
Δ = b2-4ac
Δ = 12-4·(-1)·(-30)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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