(r/9)+(r-27/3)=3

Solution for (r/9)+(r-27/3)=3 equation:

(r/9)+(r-27/3)=3

We move all terms to the left:

(r/9)+(r-27/3)-(3)=0

We add all the numbers together, and all the variables

(+r/9)+(r-9)-3=0

We get rid of parentheses

r/9+r-9-3=0

We multiply all the terms by the denominator


r+r*9-9*9-3*9=0

We add all the numbers together, and all the variables

r+r*9-108=0

Wy multiply elements

r+9r-108=0

We add all the numbers together, and all the variables

10r-108=0

We move all terms containing r to the left, all other terms to the right

10r=108

r=108/10

r=10+4/5