(s*s)-7s+12=0

Solution for (s*s)-7s+12=0 equation:

(s*s)-7s+12=0

We add all the numbers together, and all the variables

(+s*s)-7s+12=0

We add all the numbers together, and all the variables

-7s+(+s*s)+12=0

We get rid of parentheses

-7s+s*s+12=0

Wy multiply elements

s^2-7s+12=0

a = 1; b = -7; c = +12;
Δ = b2-4ac
Δ = -72-4·1·12
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-1}{2*1}=\frac{6}{2}
=3
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+1}{2*1}=\frac{8}{2}
=4
$