(s+3)(s-12)=

Solution for (s+3)(s-12)= equation:

Simplifying
(s + 3)(s + -12) = 0

Reorder the terms:
(3 + s)(s + -12) = 0

Reorder the terms:
(3 + s)(-12 + s) = 0

Multiply (3 + s) * (-12 + s)
(3(-12 + s) + s(-12 + s)) = 0
((-12 * 3 + s * 3) + s(-12 + s)) = 0
((-36 + 3s) + s(-12 + s)) = 0
(-36 + 3s + (-12 * s + s * s)) = 0
(-36 + 3s + (-12s + s2)) = 0

Combine like terms: 3s + -12s = -9s
(-36 + -9s + s2) = 0

Solving
-36 + -9s + s2 = 0

Solving for variable 's'.

Factor a trinomial.
(-3 + -1s)(12 + -1s) = 0

Subproblem 1
Set the factor '(-3 + -1s)' equal to zero and attempt to solve:

Simplifying
-3 + -1s = 0

Solving
-3 + -1s = 0

Move all terms containing s to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + -1s = 0 + 3

Combine like terms: -3 + 3 = 0
0 + -1s = 0 + 3
-1s = 0 + 3

Combine like terms: 0 + 3 = 3
-1s = 3

Divide each side by '-1'.
s = -3

Simplifying
s = -3
Subproblem 2
Set the factor '(12 + -1s)' equal to zero and attempt to solve:

Simplifying
12 + -1s = 0

Solving
12 + -1s = 0

Move all terms containing s to the left, all other terms to the right.

Add '-12' to each side of the equation.
12 + -12 + -1s = 0 + -12

Combine like terms: 12 + -12 = 0
0 + -1s = 0 + -12
-1s = 0 + -12

Combine like terms: 0 + -12 = -12
-1s = -12

Divide each side by '-1'.
s = 12

Simplifying
s = 12
Solution
s = {-3, 12}