(s+7)/2=t+1

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Solution for (s+7)/2=t+1 equation: 


x in (-oo:+oo)

(s+7)/2 = t+1 // - t+1

(s+7)/2-t-1 = 0

(s+7)/2+(2*(-t))/2+(-1*2)/2 = 0

s+2*(-t)-1*2+7 = 0

s-2*t-2+7 = 0

s-2*t+5 = 0

(s-2*t+5)/2 = 0

(s-2*t+5)/2 = 0 // * 2

s-2*t+5 = 0

x belongs to the empty set

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