(t)+(t+1)+(t+3)=

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Solution for (t)+(t+1)+(t+3)= equation:


Simplifying
(t) + (t + 1) + (t + 3) = 0
t + (t + 1) + (t + 3) = 0

Reorder the terms:
t + (1 + t) + (t + 3) = 0

Remove parenthesis around (1 + t)
t + 1 + t + (t + 3) = 0

Reorder the terms:
t + 1 + t + (3 + t) = 0

Remove parenthesis around (3 + t)
t + 1 + t + 3 + t = 0

Reorder the terms:
1 + 3 + t + t + t = 0

Combine like terms: 1 + 3 = 4
4 + t + t + t = 0

Combine like terms: t + t = 2t
4 + 2t + t = 0

Combine like terms: 2t + t = 3t
4 + 3t = 0

Solving
4 + 3t = 0

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 3t = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 3t = 0 + -4
3t = 0 + -4

Combine like terms: 0 + -4 = -4
3t = -4

Divide each side by '3'.
t = -1.333333333

Simplifying
t = -1.333333333

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